To subtract 3-fourths from 8, we must make fourths. To do this,
break off 1 from 8, and decompose it into |
4 4 |
: |
(Lesson 20, Example 4.) Therefore,
"2 from
7 is 5. |
3 4 |
from |
4 4 |
is |
1 4 |
." |
Example 2. |
6 − 1 |
2 3 |
= |
5 |
3 3 |
− 1 |
2 3 |
|
|
= |
4 |
1 3 |
. |
"1 from 5 is 4. |
2 3 |
from |
3 3 |
is |
1 3 |
." |
Example 3. Subtracting mixed numbers. Let us now compare this problem
with the previous one. We cannot take |
2 3 |
from |
1 3 |
. Therefore, we will again |
write
but here we will add the |
3 3 |
to |
1 3 |
: |
6 |
1 3 |
= |
5 |
3 3 |
+ |
1 3 |
|
|
= |
5 |
4 3 |
. |
Therefore,
6 |
1 3 |
− 1 |
2 3 |
= 5 |
4 3 |
− 1 |
2 3 |
= 4 |
2 3 |
. |
"1 from 5 is 4. |
2 3 |
from |
4 3 |
are |
2 3 |
." |
Break off 1 from 4. Express it as |
8 8 |
, and add it to |
1 8 |
: |
4 |
1 8 |
= 3 |
8 8 |
+ |
1 8 |
= 3 |
9 8 |
. |
Now the mystery if any is, How does that numerator get to be 9?
9 is the sum of the original numerator 1 and denominator 8:
Example 5. Write the missing numerator: 9 |
2 5 |
= 8 |
? 5 |
7 is the sum of denominator plus numerator: 5 + 2.
Example 6. 9 |
2 7 |
− 3 |
5 7 |
= ? |
9 |
2 7 |
becomes 8 |
9 7 |
. The improper numerator 9 is the sum of the |
denominator and numerator of |
2 7 |
: 7 + 2 = 9. |
Solution. First, we must make the
denominators the same:
We cannot take |
3 4 |
from |
2 4 |
; therefore, on breaking off 1 from 6, the
|
fraction |
2 4 |
becomes 4-fourths + 2 -fourths = 6-fourths: |
" |
3 4 |
from |
6 4 |
is |
3 4 |
. 2 from 5 is 3." |
Please "turn" the page and do some
Problems.
or
Continue on to the next Lesson.
Previous Section
Introduction | Home | Table of Contents
Please make a donation to keep TheMathPage online. Even $1 will help.
Copyright © 2001-2007 Lawrence Spector
Questions or comments?
E-mail: themathpage@nyc.rr.com
|